... electric circuit of n turns of wire conveying a known current , and to measure the potential ( or mechanical ) energy of the circuit under those conditions . The induction is equal to the potential energy of the circuit divided by n ...
... electric field in the base region : 1 E ( x ) = - KT . ( x ) . dng ( x ) n For the hole current in the n ( bulk ) region : Jp ( x ) = aDp [ RT P ( X ) E ( X ) - KT n dp ( x ) - dx Substituting for E ( x ) in the above dp Jp ( x ) ...
... N Electric Cooperative Long 2 N Y Alcan Ingot , Sebree Aluminum Plant Long 1 Y Y Allegheny Power Service Corporation Long 30 Y Y American Electric Power , Inc. Long 49 N N American Forests Long 63 N N Anoka Municipal Utility Short 5 N N ...
... electric field component E = E1 + E2 + E3 + ... + E2N satisfy the Helmholtz Eq . ( 6.2 ) , where ko = 2π / λο and 20 is the free space wavelength . The N electric N fields are expressed as slowly varying envelopes N N ΣΕ1 = Σφ ; ( x , z ) ...
... n n- , k ... k ! 1 n | k | = 1 k ! k = 1 k ij The natural requirements are also related to the degree of the phase ... electric field is essential in the centr- al region of the accelerator . By the rule form this region we obtain ...
... electric dipole approximation justified at optical frequencies , as mentioned in Section 1.2 . We shall assume that the magnetic permeability in all layers is the same and ... N - N We arrive at a quartic equation of the following form.
Wai-Kai Chen. Ec ES n Electric field (a) n-epi p EB Ec Depleted p p Substrate p ES Ec Electric field Breakdown voltage n-epi EB Ec (c) (a) (b) Depleted p Substrate Total dose in n-epi (Qc) n ES Ec Electric field n-epi EB Ec (b) n (c) ...